10x+x^2=36

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Solution for 10x+x^2=36 equation:


Simplifying
10x + x2 = 36

Solving
10x + x2 = 36

Solving for variable 'x'.

Reorder the terms:
-36 + 10x + x2 = 36 + -36

Combine like terms: 36 + -36 = 0
-36 + 10x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '36' to each side of the equation.
-36 + 10x + 36 + x2 = 0 + 36

Reorder the terms:
-36 + 36 + 10x + x2 = 0 + 36

Combine like terms: -36 + 36 = 0
0 + 10x + x2 = 0 + 36
10x + x2 = 0 + 36

Combine like terms: 0 + 36 = 36
10x + x2 = 36

The x term is 10x.  Take half its coefficient (5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
10x + 25 + x2 = 36 + 25

Reorder the terms:
25 + 10x + x2 = 36 + 25

Combine like terms: 36 + 25 = 61
25 + 10x + x2 = 61

Factor a perfect square on the left side:
(x + 5)(x + 5) = 61

Calculate the square root of the right side: 7.810249676

Break this problem into two subproblems by setting 
(x + 5) equal to 7.810249676 and -7.810249676.

Subproblem 1

x + 5 = 7.810249676 Simplifying x + 5 = 7.810249676 Reorder the terms: 5 + x = 7.810249676 Solving 5 + x = 7.810249676 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + x = 7.810249676 + -5 Combine like terms: 5 + -5 = 0 0 + x = 7.810249676 + -5 x = 7.810249676 + -5 Combine like terms: 7.810249676 + -5 = 2.810249676 x = 2.810249676 Simplifying x = 2.810249676

Subproblem 2

x + 5 = -7.810249676 Simplifying x + 5 = -7.810249676 Reorder the terms: 5 + x = -7.810249676 Solving 5 + x = -7.810249676 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + x = -7.810249676 + -5 Combine like terms: 5 + -5 = 0 0 + x = -7.810249676 + -5 x = -7.810249676 + -5 Combine like terms: -7.810249676 + -5 = -12.810249676 x = -12.810249676 Simplifying x = -12.810249676

Solution

The solution to the problem is based on the solutions from the subproblems. x = {2.810249676, -12.810249676}

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